X^2+20x-152=0

Solution for X^2+20x-152=0 equation:

X^2+20X-152=0

a = 1; b = 20; c = -152;
Δ = b2-4ac
Δ = 202-4·1·(-152)
Δ = 1008
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$X_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$X_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{1008}=\sqrt{144*7}=\sqrt{144}*\sqrt{7}=12\sqrt{7}$
$X_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(20)-12\sqrt{7}}{2*1}=\frac{-20-12\sqrt{7}}{2}
$
$X_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(20)+12\sqrt{7}}{2*1}=\frac{-20+12\sqrt{7}}{2}
$